Calculate the work done by 10g of an ideal gas of molecular weight 44 in expanding reversibly and isothermally from a volume of 5 to 10 litre at 300K.
A
93.93cal
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B
−63.63cal
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C
−93.93cal
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D
63.63cal
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Solution
The correct option is C−93.93cal W=−2.303nRTlog10V2V1
Number of moles of ideal gas n=10g44g/molR=1.987cal/KT=300KAs,V2V1=105=2
On substituting the values, we get W=−2.303×1044×1.987×300×log102
On solving, we get: W=−93.93cal