Calculate the work done by a coolie in carrying a load of mass $10$ kg on his head when he walks uniformly a distance of $5$ in the (i) horizontal direction (ii) vertical direction. ( Take $g = 10 m / s^{2}$ ).

500,0

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0,500

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1,500

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500,3

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Solution

The correct option is A 500,0
Consider the following,
work done is written as W = F.s = FsCosθ here F is the force applied, s is the displacement caused such that
F = mg = 10 X 10 = 100 N s
W( horizontal direction)= FsCos(0)=500J , θ is the angle between (vectors) F and s now,
as F and s are perpendicular for vertical direction, θ = 90 thus, W = FsCos90 = 0

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Calculate the work done by a coolie in carrying a load of mass 10 kg on his head when he walks uniformly a distance of 5 in the (i) horizontal direction (ii) vertical direction. ( Take g=10m/s2).

Calculate the work done by a coolie in carrying a load of mass $10$ kg on his head when he walks uniformly a distance of $5$ in the (i) horizontal direction (ii) vertical direction. ( Take $g = 10 m / s^{2}$ ).