wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the work done by the force F when the block moves from x=0 m to x=6.0 m

123078_bf3ae5cde65e41be89830703afe1d641.png

A
4 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 3 J
The work done by the force is W=70Fdx=20Fdx+32Fdx+43Fdx+64Fdx
From the graph force
for x=0 to x=2, F0x0=0202F=x
for x=2 to x=3, F=2
for x=3 to x=4, F=0
for x=4 to x=6, F0x4=0+146F=x2+2
now
W=20xdx+322dx+0+64(x2+2)dx+0
W=(42)+2(32)12(36162)+2(64)=2+25+4=3J
Ans:(D)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Work Done
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon