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Lattice Energy

Calculate the...

Question

Calculate the work done during combustion of $0.138$ kg of ethanol, $C_{2} H_{5} O H_{(l)}$ at $300$ K.

[Given: $R = 8.314$ $J k^{- 1}$ $m o l^{- 1}$ ; molar mass of ethanol $= 46$ g $m o l^{- 1}$ .]

- 7482 J

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7482 J

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- 2494 J

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2494 J

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Solution

The correct option is D $7482 J$
$C_{2} H_{5} O H_{(l)} + 3 O_{2} (g) \to 2 C O_{2} (g) + 3 H_{2} O_{(l)}$

0.138 kg of ethanol $= \frac{0.138 k g \times 1000 g / k g}{46 g / m o l} = 3 m o l$

$3 C_{2} H_{5} O H + 9 O_{2} \to 6 C O_{2} + 9 H_{2} O$
$Δ n = 6 - 9 = - 3$

Work $W = - Δ n R T$

$W = - (- 3) \times 8.314 \times 300$
$W = 7482 J$

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Similar questions

R = 8.314 J K^{- 1} m o l^{- 1}

R = 8.314 J K^{- 1} {m o l}^{- 1}

0.090 k g

= 30

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C_{2} H_{5} O H (l) + 3 O_{2} (g) \to 2 C O_{2} (g) + 3 H_{2} O (l)

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(R = 8.314 J k^{- 1} m o l^{- 1})

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