Question

Calculate the work done for a reversible isothermal expansion of one mole of an ideal gas at ${127}^{\circ }C$ from a volume of $10d{m}^3$ to $20d{m}^3$

• A. -2305.3 J
• B. 2305. 3 J
• C. -2306.3 J
• D. 2306.3 J

Answer 1

The correct option is A -2305.3 J

Work done for a reversible isothermal expansion can be given by:

$w=-2.303nRTlog\left(\frac{V_2}{V_1}\right)$

$w=-2.303\times 1\times 8.314\times 400log\left(\frac{20}{10}\right)$

$w=-2305.3J$