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Question

Calculate the work done (in calorie) by 10 g of an ideal gas of molar mass 16 g in expanding reversibly and isothermally from a volume of 5 L to 15 L at 300 K.

A
W = 172.48 cal
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B
W = 319.93 cal
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C
W = 352.57. cal
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D
W = 409.37 cal
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Solution

The correct option is D W = 409.37 cal
Number of moles of ideal gas = 1016 mol
R = 1.987 cal deg1mol1 T = 300 K
Final volume V2 = 15 L , initial volume = 5 L
We know,
W = 2.303nRT logV2V1
W = 2.303×1016×1.987×300×log 3
W = 409.37 cal



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