Calculate the work done (in calorie) by 10 g of an ideal gas of molar mass 16 g in expanding reversibly and isothermally from a volume of 5 L to 15 L at 300 K.
A
W = −172.48 cal
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B
W = −319.93 cal
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C
W = −352.57. cal
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D
W = −409.37 cal
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Solution
The correct option is D W = −409.37 cal Number of moles of ideal gas = 1016 mol R = 1.987 cal deg−1mol−1 T = 300 K Final volume V2 = 15 L , initial volume = 5 L We know, W = −2.303nRTlogV2V1 W = −2.303×1016×1.987×300×log3 W = −409.37 cal