Question

CALCULATE THE WORK DONE IN CALORIES WHEN 5 MOLES OF AN IDEAL GAS ARE COMPRESSED ISOTHERMALLY AND REVERSIBLY FROM A OF 1.5PRESSURE OF 15 atmAT 27 DEGREE C

Answer 1

Work done,w = -nRT(2.303) log $\frac{{\mathrm{p}}_1}{{\mathrm{p}}_2}$

w = - 5mol $\times$1.98588​ cal mol^-1 K^-1 $\times$298 K $\times$2.303$\times$log $\frac{1.5}{15}$

w = 6814.4876 cal
​ = 6.814 kcal