Question

Calculate the work done (in J) when 4.5 g of $H_2{O}_2$ reacts againsts a pressure of 1 atm at ${25}^{0}C?$
$2H_2{O}_2\left(l\right)\to O_2\left(g\right)+2H_{2}O\left(l\right)$

• A. $-1\cdot 63\times {10}^2$
• B. $4\cdot 5\times {10}^2$
• C. $3\cdot 2\times {10}^2$
• D. $-6\cdot 1\times {10}^2$

Answer 1

Answer: (A)

$-1\cdot 63\times {10}^2$

$w=-P\Delta V=-\Delta n_{g}RT=-\frac{4\cdot 5}{34\times 2}\times 8\cdot 314\times 298$
$w=-1\cdot 63\times {10}^{2}J.$