Calculate the work done (in J) when 4.5 g of $H_{2} O_{2}$ reacts against a pressure of 1 atm at 25C ?
$2 H_{2} O_{2} (ℓ) \to O 2 (g) + 2 H_{2} O (ℓ)$

- 1.63 \times 10^{2}

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4.5 \times 10^{2}

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3.2 \times 10^{2}

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- 6.1 \times 10^{2}

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Solution

The correct option is A $- 1.63 \times 10^{2}$
$w = - P Δ V$ $= - Δ n_{g} R T = - \frac{4.5}{34 \times 2} \times 8.314 \times 298$
$w = - 1.63 \times 10^{2} J$

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