calculate the work done in joule when 3 moles of an ideal gas expand isothermally and reversibly from 10 atm to 1 atm. what will be the work done if the expansion is against constant pressure of 1atm.
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Solution
Work done for isothermal reversible expansion:
w = nRT ln (p1/ p2)
= 3 mol8.314 JK-1mol-1273 K ln (1/10)
= -15678.684 J
Work done against constant pressure, w = -nRT ln(V2/V1)