Calculate the work done in lifting $100 k g$ of water through a vertical height of $6 m$ . Take $g = 10 m s^{- 1}$ .

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Solution

Step 1: Data provided,
$M a s s (m) = 100 k g h e i g h t (h) = 6 m$
Step 2: Formula used,
$W o r k = F o r c e \times D i s p l a c e m e n t F o r c e = M a s s \times a c c e l e r a t i o n$
Step 3: Calculation,
$T h e m i n i m u m f o r c e r e q u i r e d t o l i f t t h e b o d y o f m a s s m u p w a r d (F) = m g W o r k = f o r c e \times D i s p l a c e m e n t = m g \times h = m g h = 100 k g \times 10 m s^{- 2} \times 6 m = 6000 J$
Hence, the work done is 6000 J.

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