Calculate the work done in raising a stone of mass 4 kg and specific gravity 2 immersed in water from a depth of 3 m to 1 m below the surface.

Open in App

Solution

Density of water, d = 1000 kg/ $m^{3}$
Density of stone, D = 2000 kg/ $m^{3}$
Force, F = Weight of stone in water = mg (1 - $\frac{d}{D}$ ) = 4 $\times$ 9.8 $\times$ (1 - $\frac{1}{2}$ ) = 19.6 N
Work done = F $\times$ S = 19.6 $\times$ (3 - 1) = 39.2 J

Suggest Corrections

Similar questions

Q. Calculate the work done in raising a stone of mass 6 kg of specific gravity 2, immersed in water from a depth of 4m to 1m below the surface of water

(g = 10 m s^{- 2})

Q. Calculate the work done in raising a stone of mass

5 k g

and specific gravity

3

, lying at the bed of a lake through a height of

5 m

A wooden cube of side 10 cm and specific gravity 0.8 floats in water with its upper surface horizontal. What depth of the cube remains immersed? what mass of aluminum of specific gravity 2.7 must be attached to

(i)The upper surface

(ii) The lower surface so that the cube will be just immersed

Q. Find the work done in lifting a stone of mass 10 Kg and specific gravity 3 from the bed of a lake to a height of 6 m in water.

Q. A wooden cube of side 10 cm and specific gravity 0.8 floats in water with its upper surface horizontal.What depth of the cube remains immersed? What mass of aluminimum of specific gravity 2.7 must be attached to
i) the upper surface
ii) the lower surface so that the cube will be just immersed?

Join BYJU'S Learning Program

Calculate the work done in raising a stone of mass 4 kg and specific gravity 2 immersed in water from a depth of 3 m to 1 m below the surface.

Density of water, d = 1000 kg/m3 Density of stone, D = 2000 kg/m3 Force, F = Weight of stone in water = mg (1 - dD) = 4 × 9.8 × (1 - 12) = 19.6 N Work done = F × S = 19.6 × (3 - 1) = 39.2 J

Density of water, d = 1000 kg/ $m^{3}$
Density of stone, D = 2000 kg/ $m^{3}$
Force, F = Weight of stone in water = mg (1 - $\frac{d}{D}$ ) = 4 $\times$ 9.8 $\times$ (1 - $\frac{1}{2}$ ) = 19.6 N
Work done = F $\times$ S = 19.6 $\times$ (3 - 1) = 39.2 J