Question

Calculate the work done when 1 mol of zine dissolves in hydrochloric acid at 273 K in

(a) an open beaker,

(b) a closed beaker at 300K

Answer 1

$\left(a\right)$ An open beaker,

$P=1$ $atm$

$n=1$ $mole$,

$V=\frac{1\times 0.0821\times 273}{1}$

$V=22.4$ $litres$

$W=-P_{ext}\left(\Delta V\right)$

$⟹W=-1\times (22.4-0)$

$⟹W=-22.4$ $L-atm$

$⟹W=-2270.46$ $J$

$\left(b\right)$ Workdone will be zero in closed container as volume will remain constant.