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Question

Calculate the work done when 5 moles of an ideal gas at 300K are expanded isothermally from an initial pressure of 4×105 Pa to a final pressure of 1×105 Pa against a constant external pressure of 105 Pa. (5×8.314×300=12470)

A
9.35 kJ
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B
16.9 kJ
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C
Zero
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D
+16.9 kJ
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Solution

The correct option is B 16.9 kJ
Solution:- (B) 16.9kJ
As the gas is expanded isothermally, thus work done is given by-
W=2.303nRTlogPiPf
Given that:-
n=5 moles
R=8.314J/molK
T=300K
Pi=4×105Pa
Pf=105Pa
W=2.303×(5×8.314×300)log4×1051×105
W=2.303×12470×log4(5×8.314×300=12470)
W=17.29kJ16.9kJ
Hence the work done will be 16.9kJ.

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