Question

Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h?

Answer 1

Given:
Mass of the car = 1500 kg, and
velocity of car = 60 km/h $=\frac{60\times 1000m}{3600s}=\frac{50}{3}m/s$
Then the work required to stop the car = Kinetic energy of car
$=\frac{1}{2}m{v}^2-\frac{1}{2}m{\left(0\right)}^2=\frac{1}{2}\times 1500\times {\left(\frac{50}{3}\right)}^2=208333.3J$