Question

Calculate total number of atoms present in 98 g of $H_{2}S{O}_4$ ?

Answer 1

Step 1:

98 g $H_{2}S{O}_4$ contains 1 mole of $H_{2}S{O}_4$.

1 mole of $H_{2}S{O}_4$ contains 1 mole of atoms.

$\therefore$ 98 g $H_{2}S{O}_4$ contains 1 mole of atoms.

Total number of atoms in one molecule = 7 atoms.

Step 2:

Number of molecule = $1\times N_A$

Number of sulphur atoms = $n\times N_A$

Total number of atoms = $7\times N_A$

Hence, total number of atoms in 98 g $H_{2}S{O}_4$ is $7N_A$