Question

Calculate total number of optical isomers in following compound:

• A. 2
• B. 4
• C. 3
• D. 8

Answer 1

The correct option is B 4

Total number of optical isomers = $2^{n-1}$, where n = no. of chiral or stereo centers.

Here, $n=3=>2^{3-1}=4$

$\therefore$ number of optical isomers = 4