Calculate G- for conversion of oxygen to ozone 3-2O2g - O3g at 298K- if Kp for this conversion is 2-47 - 10-29Use log2-47 - 0-4

G^∘= 2.303 RT log K_p= 2.303×8.314×298 × log(2.47×10^29)j/mol=163kj/mol ...

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Equilibrium Constant and Standard Free Energy Change

Calculate G∘ ...

Question

Calculate $△ G^{\circ}$ for conversion of oxygen to ozone
$3 / 2 O_{2} (g) \to O_{3} (g) a t 298 K, i f K_{p}$ for this conversion is 2.47 $\times$ $10^{- 29}$
(Use log(2.47) = 0.4)

163 K J m o l^{- 1}

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2.4 X 10^{2} K J m o l^{- 1}

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1.63 K J m o l^{- 1}

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2.38 X 10^{6} K J m o l^{- 1}

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Solution

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Δ G^{o}

(3 / 2) O_{2} (g) ⇌ O_{3} (g)

298 K

K_{P}

2.47 \times 10^{- 29}

Δ G^{\circ}

\frac{3}{2} O_{2_{(g)}} \to O_{3_{(g)}}

K_{p}

2.47 \times 10^{- 29}

\frac{3}{2} O_{2} (g) ⟶ O_{3} (g)

K_{p}

2.47 \times 10^{- 29}

Δ_{r} G^{o}

K_{p}

\frac{3}{2} O_{2} (g) \to O_{3} (g)

2.47 \times 10^{- 29} (a t m)^{- \frac{1}{2}} .

Δ_{r} G^{o}

O_{2} (g) \to O_{2} (g)

K_{p}

2.47 \times 10^{- 29}

l o g_{10} 2.47 = 0.392

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