Calculate variance for following data :
Length of wire $1700 - 1900$ $1900 - 2100$ $2100 - 2300$ $2300 - 2500$ $2500 - 2700$
Number $10$ $16$ $20$ $8$ $6$

55, 822.22

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55, 238.51

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55832.55

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56, 823.50

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Solution

The correct option is A $55, 822.22$
$¯ x = \frac{\sum F x}{\sum F} = \frac{128800}{60} = 2146.66$
$σ^{2} = \frac{\sum F (x - ¯ x)^{2}}{\sum F} = \frac{3349333.27}{60} = 55822.22$

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Similar questions

The diagram given below, shows two paths drawn inside a rectangular field 100 cm long and 55 cm wide. The width of two paths are 10 cm and 20 cm as shown. Find the area of the path.

Q. Find the value of

2300 + 1900

Q. The temperature in the lower mantle is

(a) 2000 °C
(b) 2100 °C
(c) 2200 °C
(d) 2300 °C

List - 1	List - 2
Fraction	Temperature
A) Heavy oil	1) $u p t o 170^{0} C$
B) Anthracene oil	2) $170^{0} - 230^{0} C$
C) Light oil	3) $230^{0} - 270^{0} C$
D) Middle oil	4) $270^{0} - 400^{0} C$

Find the correlation coefficient for the data using the shortcut method for the following data.

$\begin{matrix} Q u a n t i t y (X) & P r o f i t (Y) 150 & 1600 180 & 1800 210 & 2000 240 & 2300 250 & 2500 \end{matrix}$

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Length of wire	$1700 - 1900$	$1900 - 2100$	$2100 - 2300$	$2300 - 2500$	$2500 - 2700$
Number	$10$	$16$	$20$	$8$	$6$

Calculate variance for following data : Length of wire1700−19001900−21002100−23002300−25002500−2700Number10162086

The correct option is A 55,822.22¯x=∑Fx∑F=12880060=2146.66σ2=∑F(x−¯x)2∑F=3349333.2760=55822.22

Calculate variance for following data :
Length of wire $1700 - 1900$ $1900 - 2100$ $2100 - 2300$ $2300 - 2500$ $2500 - 2700$
Number $10$ $16$ $20$ $8$ $6$

The correct option is A $55, 822.22$
$¯ x = \frac{\sum F x}{\sum F} = \frac{128800}{60} = 2146.66$
$σ^{2} = \frac{\sum F (x - ¯ x)^{2}}{\sum F} = \frac{3349333.27}{60} = 55822.22$