Question

Calculate volume of $44.8$ ${VH}_2{O}_2$ required to produce $l$ mole of $I_2$ from $KI$ solution.

• A. $2.5$ Litre
• B. $2$ Litre
• C. $0.25$ Litre
• D. $0.125$ Litre

Answer 1

Answer: (C)

$0.25$ Litre

$\left[H_2{O}_2\right]=\frac{44.8}{11.2}=A$

fanlanced are of $H_2{O}_{2}8HI$

$2KI+H_2{O}_2\to I_2+2KOH$

for are mole of $I_2$ there should be $1$ mole of $H_2{O}_2$ According to stichiometry

Molerity $=\frac{mole}{volume}$

$v=\frac{1}{4}$

$=-25$ liter

COMMENT:- correct option is $\left(C\right)$