Calculate volume of oxygen at STP required to complete the combustion of 8 L of methane.
16

Open in App

Solution

The correct option is A 16
The balanced chemical equation for the combustion of methane is given below:
${CH}_{4} (g) + 2 O_{2} (g) \to {CO}_{2} (g) + 2 H_{2} O (g)$

From the above reaction,

1 mole of ${CH}_{4}$ requires 2 moles of $O_{2}$ to complete the reaction.

Since, 1 mole of any gas at STP occupies 22.4 L, we can say

22.4 L of ${CH}_{4}$ requires $2 \times$ 22.4 L = 44.8 L of $O_{2}$ .

So, 1 L of ${CH}_{4}$ requires $\frac{44.8}{22.4}$ = 2 L of $O_{2}$ .

Hence, 8 L of ${CH}_{4}$ requires $2 \times$ 8 L = 16 L of $O_{2}$ .
16 L of $O_{2}$ is required to complete the combustion of 8 L of methane.

Suggest Corrections

Similar questions

Q. Calculate the volume of oxygen required for complete combustion of 0.25 moles of methane at STP.

Q. Calculate the volume of oxygen required for the complete combustion of

0.25 {d m}^{3}

of methane at STP.

What volume of oxygen at STP is required to effect complete combustion of 200cm³ of acetylene and what would be the volume of carbon dioxide formed?

Q. The volume of oxygen gas at STP required for the complete combustion of 200 mL of acetylene gas at STP (1 atm, 273 K) is:

Hydrogen sulphide gas burns in oxygen to yield 12.8 g of sulphur dioxide gas as under:
$2 H_{2} S + 3 O_{2} \to 2 H_{2} O + 2 S O_{2}$
(i). calculate the volume of hydrogen suulphide at STP.
Also, (ii). calculate the volume of oxygen required at STP. Which will complete the combustion of hydrogen sulphide determined in litres.

Join BYJU'S Learning Program

Calculate volume of oxygen at STP required to complete the combustion of 8 L of methane.16

Calculate volume of oxygen at STP required to complete the combustion of 8 L of methane.
16