You visited us 1 times! Enjoying our articles? Unlock Full Access!

Percentage Composition

Calculate w a...

Question

Calculate w and $△ U$ for the conversion of 1 mol of water at $100^{0} C$ to steam at 1 atm pressure. Heat of vaporization of water at $100^{0} C$ is 40.670 kJ ${m o l}^{- 1}$ . Assume ideal gas behavior.

Open in App

Solution

$H_{2} O (l) ⇌ H_{2} O (g)$
$P = 1 a t m$
$w . d = △ n_{g a s} R T$ (at constant $P$ )
$= (1 \times 8.314 \times 373) J$
$= 3101.122 J$
$\approx 3.1 k J$
$△ U = △ H_{v a p} + w$ ( $1 s t$ law of $T D$ )
$= 3.1 k J + 40.67 k J$
$= 43.77 k J$

Suggest Corrections

Similar questions

100^{0} C

41 k J . {m o l}^{- 1}

100^{0} C

H_{2} O (1) ⇌ H 2 O (g)

373

1

41

1

373

1

m o l^{- 1}

?

H_{2} O (l) ⇌ H_{2} O (g)

373

1

41 k J / m o l

1

373 K

1

^{- 1}

w

0.5

100^{\circ} C

1 a t m

100^{\circ} C

40670 J m o l^{- 1}

w

Δ U

0.5

100^{o} C

1

100^{o} C

40670 J {m o l}^{- 1}

Join BYJU'S Learning Program