Calculate wavelength, frequency wave number of light whose period is $2 \times 10^{- 10}$ second.

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Solution

$T i m e p e r i o d = 2 \times 10^{- 10} s e c f r e q u e n c y = \frac{1}{p e r i o d} = \frac{1}{2} \times 10^{- 10} = 500000000 H z w a v e l e n g h t = \frac{V e l o c i t y}{f r e q u e n c y} = \frac{299792458}{500000000} = 0.599584916 m w a v e n u m b e r = \frac{1}{w a v e l e n g h t} = \frac{1}{0.599584916} = 1.66782047599076$

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