Question

Calculating the work performed when 2 moles of hydrogen expand isothermally and reversibly at ${25}^o$C from 15 to 50 litres.

Answer 1

$W=-2.303nRT$ $log\frac{V_2}{V_1}$

$=-2.303\times 2\times 2\times 2.98$ log $\frac{50}{15}$

$=-2.303\times 4\times 298\times 0.5228$

$=-1435.1$ cal