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Question

Calculation (i) Arithmetic Mean and (ii) Standard Deviation for the following frequency distribution.

Class Interval

Frequency

20 – 25

25 – 30

30 – 35

35 – 40

40 – 45

45 – 50

8

3

15

12

8

4

N = 50

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Solution

Table of calculation

Class Interval

Frequency

f

Mid-point

X

fX

Deviation

Square of Deviation D2

f.D2

20 – 25

8

22.5

180

–12.1

146.41

1171.28

25 – 30

3

27.5

82.5

7.1

50.41

151.23

30 – 35

15

32.5

487.5

– 2.1

4.41

66.15

35 – 40

12

37.5

450

2.9

8.41

100.92

40 – 45

8

42.5

340

7.9

62.41

499.28

45 – 50

4

47.5

190

12.9

166.41

665.64

= 50

1730

=2654.5

Sum of the frequencies = N = = 50

(i) Mean = = = 34.6

(ii) == = 7.29


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