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Hardness of Water and Treatment

Calgon remove...

Question

Calgon removes hardness by forming complex compounds with the $C a^{2 +}$ and $M g^{2 +}$ ions of hard water or by adsorption.

True

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False

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Solution

The correct option is A True
Calgon is $(N a_{6} P_{6} O_{18})$ i.e. sodium hexa-metaphosphate. The calgon when added to hard water forms a soluble complex.

$N a_{2} [N a_{4} (P O_{3})_{6}] + 2 C a S O_{4} ⟶ 2 N a_{2} S O_{4} + N a_{2} [C a_{2} (P O_{3})_{6}]$ soluble

In the same way, $M g^{2 +}$ can also precipitate as $N a_{2} [M g_{2} (P O_{3})_{6}]$ and water becomes free from $M g^{2 +}$ and $C a^{2 +}$ ions.

Thus the answer is True.

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