Calomel $(H g_{2} C l_{2})$ on reaction with ammonium hydroxide gives:

H g O

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H g_{2} O

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N H_{2} - H g - H g - C l

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H g N H_{2} C l

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Solution

The correct option is D $H g N H_{2} C l$
$H g C I_{2}$ on treatment with $N H_{4} O H$ results in giving black precipitate, which is a mixture of mercury metal and basic mercury (II) amido chloride (white precipitate)

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Similar questions

Q. Balance the following equation:

H g_{2} C l_{2} + N H_{3} \to H g + H g N H_{2} C l + N H_{4} C l

State True or False.

H g_{2} C l_{2}

reacts with ammonia to form insoluble

H g N H_{2} C l

and Hg.

Q. Why 2HgO on heating gives Hg+O₂ ?

The electrical work done during the reaction at 298 K:
$2 H g_{(l)} + C l_{2 (g)} \to H g_{2} C l_{2 (s)}, i s G i v e n t h a t E_{\frac{C l_{2}}{C l^{-}}}^{\circ} = 1.36 V; E_{\frac{H g_{2} C l_{2}}{H g, C l^{-}}}^{\circ} = 0.27 V; P_{C l_{2}} = 1 a t m,$

Q. Mercurous ion on reaction with ammonium hydroxide gives :

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Calomel (Hg2Cl2) on reaction with ammonium hydroxide gives:

The correct option is D HgNH2ClHgCI2 on treatment with NH4OH results in giving black precipitate, which is a mixture of mercury metal and basic mercury (II) amido chloride (white precipitate)

Calomel $(H g_{2} C l_{2})$ on reaction with ammonium hydroxide gives:

The correct option is D $H g N H_{2} C l$
$H g C I_{2}$ on treatment with $N H_{4} O H$ results in giving black precipitate, which is a mixture of mercury metal and basic mercury (II) amido chloride (white precipitate)