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Standard XII

Chemistry

First Law of Thermodynamics

Calorie is a ...

Question

Calorie is a unit of heat or energy and it equals about 4.2 J (where 1J = 1 kg $n^{2} / s^{2})$ . Suppose we employ a system of unit in which the unit of mass equals 0.5 kg, the unit of length equals 2 metre and the unit of time is 2 second. Find the value of a calorie in new system of units.

4.2

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2.1

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16.8

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8.4

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Solution

The correct option is D 8.4
$n_{2} = n_{1} {[\frac{M_{1}}{M_{2}}]}^{1} {[\frac{L_{1}}{L_{2}}]}^{2} {[\frac{T_{1}}{T_{2}}]}^{- 2} = 4.2 {[\frac{1 k g}{0.5 k g}]}^{1} {[\frac{1 M}{2 m}]}^{2} {[\frac{1 s}{2 s}]}^{2} = 8.4$

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Calorie is a unit of heat or energy and it equals about 4.2 J (where 1J = 1 kg n2/s2). Suppose we employ a system of unit in which the unit of mass equals 0.5 kg, the unit of length equals 2 metre and the unit of time is 2 second. Find the value of a calorie in new system of units.

The correct option is D 8.4n2=n1[M1M2]1[L1L2]2[T1T2]−2=4.2[1kg0.5kg]1[1M2m]2[1s2s]2=8.4

Calorie is a unit of heat or energy and it equals about 4.2 J (where 1J = 1 kg $n^{2} / s^{2})$ . Suppose we employ a system of unit in which the unit of mass equals 0.5 kg, the unit of length equals 2 metre and the unit of time is 2 second. Find the value of a calorie in new system of units.

The correct option is D 8.4
$n_{2} = n_{1} {[\frac{M_{1}}{M_{2}}]}^{1} {[\frac{L_{1}}{L_{2}}]}^{2} {[\frac{T_{1}}{T_{2}}]}^{- 2} = 4.2 {[\frac{1 k g}{0.5 k g}]}^{1} {[\frac{1 M}{2 m}]}^{2} {[\frac{1 s}{2 s}]}^{2} = 8.4$