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Question

Calvin cycle has three stages. Identify the correct sequence.
1. Reduction during which carbohydrate is formed at the expense of photochemically made ATP and NADPH
2. Regeneration during which carbon dioxide acceptor 1, 5-RuBP is formed
3. Carboxylation during which CO2 combines with 1, 5-RuBP.

A
3, 1, 2
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B
3, 2, 1
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C
1, 2, 3
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D
2, 1, 3
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Solution

The correct option is A 3, 1, 2

CO2 fixation in dark reaction was thoroughly worked out by M. Calvin. Therefore, the complete pathway is called Calvin cycle. The first stable compound is a three-carbon compound, (3- phosphoglyceric acid), so the cycle is called C3 cycle.

It consists of three major steps:

1. Carboxylation: During which CO2 combines with 1, 5 RuBP in presence of RUBISCO to produce 3- PGA..

2. Reversal of glycolysis(Reduction)- During which carbohydrate is formed at the expense of photochemically made ATP and NADPH.

3. Regeneration of RuBP- During which Ribulose- 1,5 biphosphate is formed.

Hence, the correct answer is '3,1,2'.


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