Question

Can $152$ oranges be evenly distributed among $4$ vendors? If yes, how many oranges would one vendor get?

• A. Yes.
• B. No.
• C. One vendor woud get $13$ oranges.
• D. One vendor woud get $38$ oranges.

Answer 1

Answer: (A), (D)

One vendor woud get $38$ oranges.

For $152,$ last two digits are $52.$

$52$ is divisible by $4.$
$\therefore 152$ oranges can be evenly distributed among $4$ vendors.

$\text{Nomber of oranges each vendor would get}=\frac{\text{Total number of oranges}}{\text{Total number of vendors}}$
$=\frac{152}{4}$ oranges
$=\frac{100+52}{4}$ oranges
$=\frac{100}{4}+\frac{52}{4}$ oranges
$=25+\frac{13\times 4}{4}$ oranges
$=25+13$ oranges
​​​​​​​$=38$ oranges