Can and respectively be the LCM and HCF of two numbers? Give reason.
Given,
LCM of two numbers
HCF of two numbers
The LCM of two numbers is exactly divisible by the HCF of the numbers.
But, when divided by , it gives a quotient of and a reminder of.
is not exactly divisible by .
Hence, no , and can't be the LCM and HCF of two numbers.