Question

Can a quadrilateral ABCD be a parallelogram for the following condition?

(Enter 1 for True and 0 for False)

$\angle A={70}^{0}and\angle C={65}^0$.

Answer 1

Given the condition, $\angle A=70°$ and $\angle C=65°$

The opposite angles should be of same measures. But here $\angle A\ne \angle C$

$\therefore$ The statement is false.

Hence, the answer is zero.