Can a right angled triangle with sides 6 cm, 10 cm, and 8 cm be formed? Give reason

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Solution

Dear student,

$S i n c e, 10^{2} = 100 6^{2} = 36 8^{2} = 64 \sin c e 100 = 36 + 64 \Rightarrow 10^{2} = 6^{2} + 8^{2} S q u a r e o f l o n g e s t s i d e i s e q u a l t o s u m o f s q u a r e o f o t h e r t w o s i d e s . t h u s, H^{2} = P^{2} + B^{2} w h i c h s a t i s f i e s t h e P y t h a g o r a s t h e o r e m .$

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