Question

Can a right angled triangle with sides 6 cm, 10 cm, and 8 cm be formed? Give reason

Answer 1

Dear student,


$$\begin{gathered} Since, \\ {10}^2=100 \\ {6}^2=36 \\ {8}^2=64 \\ \sin ce100=36+64 \\ \Rightarrow {10}^2=6^2+8^2 \\ Squareoflongestsideisequaltosumofsquareofothertwosides. \\ thus,H^2=P^2+B^2 \\ whichsatisfiesthePythagorastheorem. \end{gathered}$$

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