Can d - v- -dt- 0 while - dv-dt - 0-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Acceleration

Can d | v⃗ ...

Question

Can $\frac{d | \to v |}{d t} = 0 w h i l e ∣ ∣ ∣ \frac{d \to v}{d t} ∣ ∣ ∣ \neq 0$ .

Yes always

No worries! We‘ve got your back. Try BYJU‘S free classes today!

No never

No worries! We‘ve got your back. Try BYJU‘S free classes today!

In some particular cases

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\frac{d | \to v |}{d t} \neq 0 w h i l e ∣ ∣ ∣ \frac{d \to v}{d t} ∣ ∣ ∣ = 0

∣ ∣ ∣ \frac{d \to v}{d t} ∣ ∣ ∣ a n d \frac{d | \to v |}{d t}

X - Z

\to r = v_{0} t^i + a_{0} e^{b_{0} t}^k

(\begin{matrix} \to v = \frac{d \to r}{d t} \end{matrix})

(\begin{matrix} | \begin{matrix} \to v \end{matrix} | \end{matrix})

(\begin{matrix} \frac{d \to v}{d t} \end{matrix})

∣ ∣ ∣ \frac{d \to v}{d t} ∣ ∣ ∣ \neq 0

\frac{d}{d t} | \to v | = 0

t^{2} \frac{d^{2} x}{d t^{2}} + t \frac{d x}{d t} + 2 y = 0

t^{2} \frac{d^{2} y}{d t^{2}} + t \frac{d y}{d t} - 2 x = 0

Join BYJU'S Learning Program