Can root of sin2theta -1 can be simplified as sin-theta- -1

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Trigonometric Ratio(sin,cos,tan)

Can root of s...

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Can root of sin²theta -1 can be simplified as sin(theta) -1

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{(\frac{1 + sin θ - cos θ}{1 + sin θ + cos θ})}^{2} = λ (\frac{1 - cos θ}{1 + cos θ})

λ

2 sin (\frac{θ}{2}) = \sqrt{1 + sin θ} + \sqrt{1 - sin θ}

\frac{θ}{2}

2 n π + \frac{π}{4}

2 n π + \frac{3 π}{4}

\frac{π}{4} \leq θ \leq \frac{3 π}{4}

sin \frac{θ}{2} > 0

(\frac{m^{2} - 1}{m^{2} + 1}) = sinθ .

\sec θ = \frac{5}{4}

\frac{(\sin θ - 2 \cos θ)}{(\tan θ - \cot θ)} = \frac{12}{7}

sin θ = 0.8

θ

2^{n d}

cos θ

{sin}^{2} θ + {cos}^{2} θ = 1

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