Question

Can $\tan {65}^0=\tan {25}^0+\tan {40}^0$?

If Yes answer is 1,else 0

Answer 1

We've,

$\tan \left({65}^o\right)=\tan ({25}^o+{40}^o)$

or, $\tan {65}^o=\frac{\tan {25}^o+\tan {40}^o}{1-\tan {25}^o.\tan {40}^o}$.

So $\tan {65}^o\ne \tan {25}^o+\tan {40}^o$.

So the correct answer is $0$.