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Question

Can the sum of the first few consecutive terms of the arithmetic sequence 5, 7, 9, ….be 140? What about 240?

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Solution

Let the first term of the A.P. be a + b and the common difference be a.

The given sequence is 5, 7, 9, …

a = 7 − 5 = 2

a + b = 5

2 + b = 5

b = 5 − 2 = 3

The general term of an A.P. is given by

Let the sum of n terms of the given sequence be 140.

Sum of n terms =

Comparing the above equation with general quadratic equation:

a = 2, b = 8 and c = 280

Discriminant of the above equation is:

b2 − 4ac = (8)2 − 4(2)(280)

= 64 + 2240

= 2304

As the discriminant is positive, the above equation has two solutions.

As n is the number of terms, n cannot be negative.

n = 10

Therefore, the sum of 10 consecutive terms of the given sequence is 140.

Now, let the sum of m terms of the given sequence be 240.

Sum of m terms =

Comparing the above equation with general quadratic equation:

a = 2, b = 8 and c = 480

Discriminant of the above equation is:

b2 − 4ac = (8)2 − 4(2)(480)

= 64 + 3840

= 3904

As the discriminant is positive, the above equation has two solutions.

As n is the number of terms, n cannot be negative or in decimals.

Therefore, 240 cannot be the sum of the first few consecutive terms of the given sequence.


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