Can we draw a quadrilateral ABCD with following AB = 3 cm, BC = 5 cm, AD = 4 cm, CD = 7 cm and BD = 8 cm?
No, it is impossible.
If we have the measures of all the sides of a quadrilateral and its one diagonal we draw two triangles and hence, form a quadrilateral
ABCD comprises of two triangles ∆ADB & ∆CDB
In ∆ADB, AB = 3 cm, BD = 8 cm, and AD = 4 cm
Hence AB + AD < BD
∆ADB can't be constructed.
So, quadrilateral ABCD can't be constructed.