When the class intervals are continuous but each of the given classes of unequal width, then we can find the mean with the help of any of the 3 methods :
Direct method
Assumed mean method
Step deviation method
Consider the following example.
A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.
No. of days | 0-6 | 6-10 | 10-14 | 14-20 | 20-28 | 28-38 | 38-40 |
No. of students | 11 | 10 | 7 | 4 | 4 | 3 | 1 |
Here is the solution.
CLASS INTERVAL | FREQUENCY (fi) | CLASS MARKS(xi) | fixi |
0-6 | 11 | 3 | 33 |
6-10 | 10 | 8 | 80 |
10-14 | 7 | 12 | 84 |
14-20 | 4 | 17 | 68 |
20-28 | 4 | 24 | 96 |
28-38 | 3 | 33 | 99 |
38-40 | 1 | 39 | 39 |
Total | ∑ fi = 40 | ∑ fi xi = 499 |
Mean = ∑ fi xi / ∑ fi = 499/40 = 12.475 ≈ 12.48
Note: Direct method should be used when the given data is small. Assumed mean method for intermediate data and for huge data we can use step deviation method.