Cancidates were asked to come to an interview with 3 pens each. Black, Blue, greena nd red were the permitted pen colours that the candidate could bring. The probability that a candidate comes with all 3 pens having the same colour is
The number of ways of selecting 3 pens of same colour is
4C1=4
The number of ways of selecting 3 pens of two different colours = 4C2 × 2C1=12
[∵ 3rd pen can be selected only by one of these two selected colors that's why we have multiplied with 2C1].
The number of ways of selecting 3 pens of three different colours = 4C3=4
Total number of ways = 4C1 + 4C2 × 2C1 + 4C3
=4+12+4=20
Favourable cases = 4C1=4
p(E)=420=15=0.2