CaOCl2-H2O - CaOH2-X- X-CH3CHO- Y- Y-CaOH2- CHCl3What is Y-

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Action of Water on Calcium Carbide

CaOCl2+H2O → ...

Question

$C a O C l_{2} + H_{2} O \to C a (O H)_{2} + X$ :
$X + C H_{3} C H O \to Y$ :
$Y + C a (O H)_{2} \to C H C l_{3}$
What is $Y$ ?

C H_{3} C H (O H)_{2}

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C H_{2} C l_{2}

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C C l_{3} C H O

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C C l_{3} C O C H_{3}

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Solution

The correct option is D $C C l_{3} C H O$
This is basic method of chloroform formation.
Reactions of process:
$C a O C l_{2} + H_{2} O \to C a (O H)_{2} + C l_{2}$
$C H_{3} C H O + 3 C l_{2} \to C C l_{3} C H O + 3 H C l$
$2 C C l_{3} C H O + C a (O H)_{2} \to 2 C H C l_{3}$ (chloroform)

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Similar questions

C C l_{3} C O C H_{3} + C a (O H)_{2} \to X + Y

. Here

X

and

Y

are:

B e_{2} C + H_{2} O \to B e (O H)_{2} + X

C a C_{2} + H_{2} O \to C a (O H)_{2} + Y

In the above given reactions,

X

and

Y

are respectively :

A metal carbonate X on treatment with a mineral acid liberates a gas which when passed through aqueous solution of a substance Y gives back X. The substance Y on reaction with the gas obtained at anode during electrolysis of brine gives a compound Z which can decolorise coloured fabrics. The compounds X, Y and Z respectively are

Q. In the aqueous solution, bleaching powder behaves as

C a O C l_{2} + H_{2} O \to C l_{2} + C a (O H)_{2}

The equivalent weight of

C a O C l_{2}

\frac{M}{x}

, where x is :

B e_{2} C + H_{2} O \to B e (O H)_{2} + x

C a C_{2} + H_{2} O \to C a (O H)_{2} + y

then x and y are respectively:

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CaOCl2+H2O→Ca(OH)2+X:X+CH3CHO→Y:Y+Ca(OH)2→CHCl3What is Y?

The correct option is D CCl3CHOThis is basic method of chloroform formation.Reactions of process:CaOCl2+H2O→Ca(OH)2+Cl2CH3CHO+3Cl2→CCl3CHO+3HCl2CCl3CHO+Ca(OH)2→2CHCl3 (chloroform)

$C a O C l_{2} + H_{2} O \to C a (O H)_{2} + X$ :
$X + C H_{3} C H O \to Y$ :
$Y + C a (O H)_{2} \to C H C l_{3}$
What is $Y$ ?

The correct option is D $C C l_{3} C H O$
This is basic method of chloroform formation.
Reactions of process:
$C a O C l_{2} + H_{2} O \to C a (O H)_{2} + C l_{2}$
$C H_{3} C H O + 3 C l_{2} \to C C l_{3} C H O + 3 H C l$
$2 C C l_{3} C H O + C a (O H)_{2} \to 2 C H C l_{3}$ (chloroform)