$C a O C l_{2}$ in aqueous solution changes to $C l_{2}$ . What is the average oxidation state of $C l$ in $C a O C l_{2}$ ?

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Solution

The oxidation number of chlorine in $C a O C l_{2}$ (bleaching powder) In bleaching powder, $C a (O C l) C l$ , the two $C l$ atoms are in different oxidation states i.e., one $C l^{-}$ having oxidation number of $- 1$ and the other as $O C l^{-}$ having oxidation number of $+ 1.$

Therefore, the average oxidation state of chlorine is 0.

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