Car A is moving with a speed of 36 Kmh^{-1} on a two lane road.Two cars B and C, each moving with a speed of 54 Kmh^{-1} in opposite direction on the other lane are approaching car A.At a certain ins†an t when the dis†an ce AB=dis†an ce AC=1 Km, the driver of car B decides to overtake A before C does. What must be minimum acceleration of car B so as to avoid an accident?

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On a two-lane road, car A is travelling with a speed of $36 k m h^{- 1}$ . Two cars B and C approach car A in opposite directions with a speed of $54 k m h^{- 1}$ each. At a certain instant, when the distance AB is equal to AC, both being 1 km, B decides to overtake A before C does. What minimum acceleration of car B is required to avoid an accident?

Q. On a two-lane road, car A is travelling at a speed of 36 km/hr. Two cars B and C approach car A in opposite directions with a speed of 54 km/hr each. At a certain instant, when the distance AB is equal to AC, both being 1 km, B decides to overtake A before C does. What is a minimum acceleration of car B required to avoid an accident?

Q. On a two lane road, car A is travelling with a speed of 36 km

h^{- 1}

. two cars B and C approach car A in opposite directions with a speed of 54 km

h^{- 1}

each. At a certain instant, when the distance AB is equal to AC, both being 1 km, B decides to overtake A before C does. What minimum acceleration of car B is required to avoid an accident?

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