Carbanion formation in the presence of a strong base is the easiest in -

C H_{4}

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C H_{3} - C H_{3}

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C H_{3} - C N

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C H (C N)_{3}

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Solution

The correct option is D $C H (C N)_{3}$
Carbanion can be stabilized by the presence of electron withdrawing groups. Hence, $C H_{3} - C N$ with $3 C N^{-}$ is the most easy to form the carbanion.

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