Question

Carbon atoms in compound $\left(C{N}_4\right)C_2$ are:

• A. $sp$ hybridizes
• B. $s{p}^2$ hybridized
• C. $sp$ & $s{p}^2$ hybridized
• D. $sp,s{p}^2$ & $s{p}^3$ hybridized

Answer 1

The correct option is B $s{p}^2$ hybridized

The central carbon atoms are bonded to each other by a double bond and to two other carbon atoms by single bonds.

Now the number of sigma bonds by which one central carbon atom is bonded is 3
(double bond contains one sigma and one pi bond). Thus hybridisation is $s{p}^2$.

Conclusion: hence the option (b) is correct.