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Standard XII

Chemistry

Electrometallurgy

Carbon cannot...

Question

Carbon cannot be used in the reduction of $A l_{2} O_{3}$ because:

It is expensive

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The enthalpy of formation of

C O_{2}

is more than that of

A l_{2} O_{3}

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Pure carbon is not easily available

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The enthalpy of formation of

A l_{2} O_{3}

is too high

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Solution

The correct option is D The enthalpy of formation of $A l_{2} O_{3}$ is too high
Alumina has very high enthalpy of formation.

Hence, carbon cannot be used to reduce alumina to aluminium.

Option D is correct.

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Similar questions

The enthalpies of formation of $A l_{2} O_{3}$ and $C r_{2} O_{3}$ are $- 1569 K J$ and $- 1134 K J$ respectively. $Δ H$ for the reaction

$2 A l + C r_{2} O_{3} \to 2 C r + A l_{2} O_{3}$ is

Q. The enthalpies of formation of

A l_{2} O_{3}

and

C r_{2} O_{3}

are -1596 kJ and -1134 kJ respectively.

Δ H

for the reaction,

2 A l + C r_{2} O_{3} \to 2 C r + A l_{2} O_{3}

is :

Q. When

10 g

A l

is used for reduction in each of the following alumino thermic reactions, which reaction would generate more heat and by how much ?
a.

2 A l + C r_{2} O_{3} \to A l_{2} O_{3} + 2 C r

2 A l + F e_{2} O_{3} \to A l_{2} O_{3} + 2 F e

Standard heat of formation of

A l_{2} O_{3}

C r_{2} O_{3}

and

F e_{2} O_{3}

are

- 1676 k J

- 1141 k J

and

- 822.2 k J

, respectively.

The enthalpies of formation of $A l_{2} O_{3}$ and $C r_{2} O_{3}$ are $- 1569 K J$ and $- 1134 K J$ respectively. $Δ H$ for the reaction

$2 A l + C r_{2} O_{3} \to 2 C r + A l_{2} O_{3}$ is

Q. Calculate the

Δ H^{⊖}

for the reduction of

F e_{2} O_{3} (s)

A l (s)

25^{\circ} C

. The enthalpies of formation of

F e_{2} O_{3} (s)

and

A l_{2} O_{3}

are

- 825.5

and

- 1675.7 k J m o l^{- 1}

respectively.

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Carbon cannot be used in the reduction of Al2O3 because:

The correct option is D The enthalpy of formation of Al2O3 is too highAlumina has very high enthalpy of formation. Hence, carbon cannot be used to reduce alumina to aluminium.Option D is correct.

Carbon cannot be used in the reduction of $A l_{2} O_{3}$ because:

The correct option is D The enthalpy of formation of $A l_{2} O_{3}$ is too high
Alumina has very high enthalpy of formation.

Hence, carbon cannot be used to reduce alumina to aluminium.

Option D is correct.