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Question

# Carbon is found to form two oxides which contain 42.9% and 27.3% of carbon respectively. The above data supports:

A
Law of constant proportion
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B
Law of multiple proportion
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C
Law of reciprocal proportion
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D
None of these
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Solution

## The correct option is B Law of multiple proportionI. Calculating the percentage composition of carbon and oxygen in each of the two oxides. First oxideSecond oxideCarbon42.9%27.3%(Given)Oxygen57.1%72.7% II: Calculating the masses of carbon which combine with a fixed mass i.e., one part by mass of oxygen in each of the two oxides. In the first oxide, 57.1 parts by mass of oxygen combine with carbon which is equal to 42.9 parts. ∴ 1 part by mass of oxygen will combine with carbon =42.957.1=0.751 In the second oxide 72.7 parts by mass of oxygen combine with carbon = 27.3 parts ∴ 1 part by mass of oxygen will combine with carbon =27.372.7=0.376 III: Comparing the masses of carbon which combine with the same mass of oxygen in both the oxides. The ratio of the masses of carbon that combine with the same mass of oxygen (1 part) is 0.751 : 0.376 or 2 : 1 Since this is a simple whole number ratio, the above data illustrates the law of multiple proportions.

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