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Question

Carbon monoxide in water gas, reacts with steam according to the reaction:CO(g)+H2O(g)→CO2(g)+H2(g);Keq=1.0If three volumes of water gas (containing 1:2 of CO and H2) are mixed with 3 volumes of steam, then the volume ratio of the four gases present at equilibrium is

A
1:5:1:5
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B
1:4:3:1
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C
1:5:1:1
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D
1:1:1:2
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Solution

The correct option is B 1:5:1:5CO(g)+H2O(g)→CO2(g)+H2(g);13021−x3−xx2+xKeq=x(2+x)(1−x)(3−x)=1x2+2x=3−4x+x2x=0.5Hence, the ratio for the gases, CO(g):H2O(g):CO2(g):H2(g)=0.5:2.5:0.5:2.5Or 1:5:1:5Option A is correct.

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