Question

Carbon reacts with chlorine to form $CC{l}_4$. 36 gm of carbon was mixed with 142 g of $C{l}_2$. Calculate the mass of $CC{l}_4$ produced in the reaction.

• A. 203 g
• B. 154 g
• C. 290 g
• D. 127 g

Answer 1

The correct option is B 154 g

As mass of chlorine is less than $C{l}_2$ required,. So, $C{l}_2$ is limiting reactant that is whole reaction is controlled by $C{l}_2$.

$C+2C{l}_2\to CC{l}_4$

$4\times 35.5g$ of $C{l}_2$ reacts with $12g$ of $C$.

$1gC{l}_2$ reacts with $\frac{12}{142}g$ of $C$.

$142gC{l}_2\to \frac{12}{142}\times 142C=12g$

So, mass of $C$ is in excess.

$4\times 35.5C{l}_2\to 154gCC{l}_4$

$1gC{l}_2\to \frac{154}{142}gCC{l}_4$

$142gC{l}_2\to 154gCC{l}_4$